1=10/3x-x^2

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Solution for 1=10/3x-x^2 equation: 


x in (-oo:+oo)

1 = (10/3)*x-x^2 // - (10/3)*x-x^2

x^2-((10/3)*x)+1 = 0

x^2+(-10/3)*x+1 = 0

x^2-10/3*x+1 = 0

DELTA = (-10/3)^2-(1*1*4)

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+10/3)/(1*2) or x = (10/3-(64/9)^(1/2))/(1*2)

x = 3 or x = 1/3

x in { 1/3, 3 }

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